
Exercise 14: Algebra 1.3
p.35: 1, 2, 5, 9, 13, 15, 21, 22, 25, 31, 32, 40, 45,
D3, D4
↳
:
D=
axtb
Now
the
slope
of
the
line
(
that
is
a
)
is
-1
.
(
for
example
,
we
take
two
points
#
I
4
:,,,↳h
A
(0.1121×1,41)
191
13
(
1
,
0
)
=
(
Xzcyr
)
•
•
☐
>
×
then
slope
=
=
¥0
=
-1
.
0=1%0 7
So
y=
-
✗
c-
b.
Now
we
plug
into
the
point
#
(
D.
1)
L
,
:
(
vertical
line
so
all
points
on
Li
share
the
same
✗
-
coordinat e
)
so
I
=
-
Otb
b=
,
y
✗
=
I
☐
Lz
Y
=
I
↳
:
it
passing
through
10 ,0
)
&
(
1.
1)
D=
✗
Lx
y
=
-
✗
+
I